Two stones are thrown up simultaneously from the edge of a cliff 240 m high with initial speed of 10 m/s and 40 m/s respectively. Which of the following graph best represents the time variation of relative position of the second stone with respect to the first ? (assume stones do not rebound after hitting the ground and neglect air resistance, take g = 10 m/s 2 )
(The figures are schematic and not drawn to scale.)
Text Solution
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–240 = 10 t – 
× 10t 2
5t 2 – 10t – 240 = 0
t 2 – 2t – 48 = 0
t 2 – 8t + 6t – 48 = 0
t = 8,–6
The first particle will strike ground at 8 seconds upto 8 second, relative velocity is 30m/s and relative acceleration is zero. After 8 second magnitude of relative velocity will increase upto 12 seconds when second particle strikes the ground.
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